从文本文件中读取输入并将其解压缩 – C

从文本文件中读取输入并将其解压缩 – C,第1张

概述我正在尝试逐行读取文本文件并将数据提取到我的程序中.本质上,C程序将读取已经采用以下格式的输入文件: Republican Senator John McMahon Democrat Mayor Steven Markel Republican Judge Matt Stevens Democrat Senator Anthony Quizitano S R 我正在尝试逐行读取文本文件并将数据提取到我的程序中.本质上,C程序将读取已经采用以下格式的输入文件:

Republican Senator John McMahon     Democrat Mayor Steven Markel     Republican Judge Matt Stevens     Democrat Senator Anthony Quizitano     S R     M D     J R     ...     ..     ..

格式基本上是前3行包括Party,position和name,接下来的行表示“结果”,其形式为:

[第一封信] [党投票]

所以,例如,如果你看到S R,这意味着对参议员投了1票,那就是共和党候选人.

这是我到目前为止所拥有的:

#include<fstream>            int main()            {            std::ifstream input("file.txt");            }

这是我的理解,这将允许我输入文件,并逐行进行,但我不知道如何从这里开始实现这个…任何帮助?

谢谢!

解决方法 为了娱乐和荣耀,这是一个基于Boost Spirit的实现.我添加了更多假投票输入,只是因此可能会显示一些内容.

>我不确定候选人和投票之间是否存在1:1的关系(我不是美国公民,我不知道列出的候选人是投票还是投票).所以我决定只使用假数据.

const std::string input =     "Republican Senator John McMahon\n"    "Democrat Senator Anthony Quizitano\n"    "S R\n"    "S R\n"    "S R\n"    "Democrat Mayor Steven Markel\n"    "Republican Judge Matt Stevens\n"    "M D\n"    "J R\n"    "S R\n"    "S R\n";

但是,该代码可用于这两个目的.
>我将输入显示的顺序变得不重要.
>但是,您可以断言,单个字母(S,M,J)实际上对应于该点之前列出的位置.通过使用posletter_check取消注释检查来启用此功能

请参阅http://liveworkspace.org/code/d9e39c19674fbf7b2419ff88a642dc38的现场演示

#define BOOST_SPIRIT_USE_PHOENIX_V3#define BOOST_RESulT_OF_USE_DECLTYPE#include <boost/fusion/adapted.hpp>#include <boost/spirit/include/qi.hpp>#include <boost/spirit/include/phoenix.hpp>#include <iomanip>namespace qi    = boost::spirit::qi;namespace phx   = boost::phoenix;struct CandIDate { std::string party,position,name; };BOOST_FUSION_ADAPT_STRUCT(CandIDate,(std::string,party)(std::string,position)(std::string,name))typedef std::map<std::pair<char,char>,size_t> Votes;typedef std::vector<CandIDate> CandIDates;template <typename It>    struct parser : qi::grammar<It>{    mutable Votes _Votes;    mutable CandIDates _candIDates;    parser() : parser::base_type(start)    {        using namespace qi;        using phx::bind; using phx::ref; using phx::val;        start = (line % eol) >> *eol >> eoi;        line =               Vote      [ phx::bind(&parser::register_Vote,phx::ref(*this),_1) ]            | candIDate [ phx::push_back(phx::ref(_candIDates),_1) ]            ;        Vote %= graph                           // Comment the following line to accept any single                        // letter,even if a matching position wasn't seen                        // before:                        [ _pass = phx::bind(&parser::posletter_check,_1) ]              >> ' '             >> char_("RD")            ;        candIDate = (string("Republican") | string("Democrat"))            >> ' '             >> as_string [ +graph ]            >> ' '             >> as_string [ +(char_ - eol) ]            ;    }  private:    bool posletter_check(char posletter) const    {        for (auto& c : _candIDates)            if (posletter == c.position[0])                return true;        return false;    }    voID register_Vote(Votes::key_type const& key) const    {        auto it = _Votes.find(key);        if (_Votes.end()==it)            _Votes[key] = 1;        else            it->second++;    }    qi::rule<It,Votes::key_type()> Vote;    qi::rule<It,CandIDate()> candIDate;    qi::rule<It> start,line;};int main(){    const std::string input =         "Republican Senator John McMahon\n"        "Democrat Senator Anthony Quizitano\n"        "S R\n"        "S R\n"        "S R\n"        "Democrat Mayor Steven Markel\n"        "Republican Judge Matt Stevens\n"        "M D\n"        "J R\n"        "S R\n"        "S R\n";    std::string::const_iterator f(std::begin(input)),l(std::end(input));    parser<std::string::const_iterator> p;    try    {        bool ok = qi::parse(f,l,p);        if (ok)           {            std::cout << "\ncandIDate List\n";            std::cout << "------------------------------------------------\n";            for (auto& c : p._candIDates)                std::cout << std::setw(20) << c.name << " (" << c.position << " for the " << c.party << "s)\n";            std::cout << "\nVote distribution:\n";            std::cout << "------------------------------------------------\n";            for (auto& v : p._Votes)                std::cout << '(' << v.first.first << "," << v.first.second << "): " << v.second << " Votes " << std::string(v.second,'*') << "\n";        }        else std::cerr << "parse Failed: '" << std::string(f,l) << "'\n";        if (f!=l) std::cerr << "trailing unparsed: '" << std::string(f,l) << "'\n";    } catch(const qi::expectation_failure<std::string::const_iterator>& e)    {        std::string frag(e.first,e.last);        std::cerr << e.what() << "'" << frag << "'\n";    }}

输出:

candIDate List------------------------------------------------        John McMahon (Senator for the Republicans)   Anthony Quizitano (Senator for the Democrats)       Steven Markel (Mayor for the Democrats)        Matt Stevens (Judge for the Republicans)Vote distribution:------------------------------------------------(J,R): 1 Votes *(M,D): 1 Votes *(S,R): 5 Votes *****
总结

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