![如何在Go中将[4] uint8转换为uint32?,第1张 如何在Go中将[4] uint8转换为uint32?,第1张](/aiimages/%E5%A6%82%E4%BD%95%E5%9C%A8Go%E4%B8%AD%E5%B0%86%5B4%5D+uint8%E8%BD%AC%E6%8D%A2%E4%B8%BAuint32%EF%BC%9F.png)
package mainimport ( "encoding/binary" "fmt")func main() { u8 := []uint8{0, 1, 2, 3} u32LE := binary.LittleEndian.Uint32(u8) fmt.Println("little-endian:", u8, "to", u32LE) u32BE := binary.BigEndian.Uint32(u8) fmt.Println("big-endian: ", u8, "to", u32BE)}输出:
little-endian: [0 1 2 3] to 50462976big-endian: [0 1 2 3] to 66051
Go 二进制包功能通过一系列移位实现。
func (littleEndian) Uint32(b []byte) uint32 { return uint32(b[0]) | uint32(b[1])<<8 | uint32(b[2])<<16 | uint32(b[3])<<24}func (bigEndian) Uint32(b []byte) uint32 { return uint32(b[3]) | uint32(b[2])<<8 | uint32(b[1])<<16 | uint32(b[0])<<24}欢迎分享,转载请注明来源:内存溢出
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