
目录
二叉搜索树的删除(较复杂)
Gitee代码:二叉搜索树
二叉搜索树的删除(较复杂)
bool Erase(const K& key)
{
Node* parent = nullptr;
Node* cur = _root;
while (cur)
{
if (cur->_key < key)
{
parent = cur;
cur = cur->_right;
}
else if (cur->_key > key)
{
parent = cur;
cur = cur->_left;
}
else
{
// 删除
if (cur->_left == nullptr)
{
if (cur == parent->_left)
{
parent->_left = cur->_right;
}
else
{
parent->_right = cur->_right;
}
delete cur;
}
else if (cur->_right == nullptr)
{
if (cur == parent->_left)
{
parent->_left = cur->_left;
}
else
{
parent->_right = cur->_left;
}
delete cur;
}
else
{
// 找到右树最小节点去替代删除
Node* minRightParent = cur;
Node* minRight = cur->_right;
while (minRight->_left)
{
minRightParent = minRight;
minRight = minRight->_left;
}
cur->_key = minRight->_key;
if (minRight == minRightParent->_left)
minRightParent->_left = minRight->_right;
else
minRightParent->_right = minRight->_right;
delete minRight;
}
return true;
}
}
return false;
}
(较难)对于2个孩子的节点删除,用替代法删除法
上面代码的删除,如果全删除的话,会发现程序崩溃了——出现空指针
改进===>
Gitee代码:二叉搜索树===>>>会发现不会崩溃
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